- QuestionA line parallel to y=4x+6 passes through (5,10). What is the y-coordinate of the point where this line crosses the y-axis?Model answerThe line is parallel to y=4x+6, which means that it has the same slope as y=4x+6. Since the line passes through (5,10), we can use the point-slope form of a line to find the equation of the line: y−10=4(x−5)y−10=4x−20y=4x−10 Now that we have the equation of the line, we can find the y-coordinate of the point where the line crosses the y-axis by substituting x=0 into the equation: y=4⋅0−10=−10.Reference answerSince the line is parallel to y=4x+6, we know that its slope is 4. Thus the equation of the line is y=4x+b where b is the y-intercept. Plugging (5,10) into this gives 10=4⋅5+b⇒b=−10 which is what we wanted.Problem sourceMATH Algebra Level 4Evaluation resultCorrect
Key: Correct Incorrect False positive
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